Organic Chemistry

study guides for every class

that actually explain what's on your next test

$Br^+$

from class:

Organic Chemistry

Definition

$Br^+$ is a positively charged bromine cation that is a key intermediate in nucleophilic aromatic substitution reactions. It serves as an electrophile that can attack and displace substituents on aromatic rings, facilitating the substitution of new functional groups.

congrats on reading the definition of $Br^+$. now let's actually learn it.

ok, let's learn stuff

5 Must Know Facts For Your Next Test

  1. $Br^+$ is a bromonium ion that acts as an electrophile in nucleophilic aromatic substitution reactions.
  2. The formation of $Br^+$ is the rate-determining step in S$_N$Ar reactions, as it creates a partially positively charged carbon that is susceptible to nucleophilic attack.
  3. $Br^+$ is typically generated in situ from aryl halides (e.g., bromobenzene) through the action of a strong base or other activating agents.
  4. The presence of electron-withdrawing groups on the aromatic ring can stabilize the $Br^+$ intermediate and facilitate the S$_N$Ar reaction.
  5. Nucleophiles can then attack the $Br^+$ intermediate, displacing the bromine and forming a new carbon-nucleophile bond.

Review Questions

  • Explain the role of $Br^+$ in the mechanism of nucleophilic aromatic substitution (S$_N$Ar).
    • $Br^+$ is a key intermediate in the S$_N$Ar mechanism, acting as an electrophile that is attacked by a nucleophile. The formation of $Br^+$ is the rate-determining step, as it creates a partially positively charged carbon that is susceptible to nucleophilic attack. The presence of electron-withdrawing groups on the aromatic ring can stabilize the $Br^+$ intermediate and facilitate the substitution reaction. Once formed, the nucleophile can then attack the $Br^+$ intermediate, displacing the bromine and forming a new carbon-nucleophile bond.
  • Compare and contrast the mechanisms of nucleophilic aromatic substitution (S$_N$Ar) and electrophilic aromatic substitution (S$_E$Ar), and explain how $Br^+$ is involved in each.
    • In S$_N$Ar, $Br^+$ acts as an electrophile that is attacked by a nucleophile, whereas in S$_E$Ar, an electrophile directly attacks the aromatic ring, displacing a hydrogen. The formation of $Br^+$ is the rate-determining step in S$_N$Ar, as it creates a partially positively charged carbon that is susceptible to nucleophilic attack. In contrast, S$_E$Ar does not involve the formation of a bromonium ion intermediate like $Br^+$. Instead, the electrophile directly attacks the aromatic ring, leading to the substitution of a new functional group. While both mechanisms involve the substitution of functional groups on aromatic rings, the specific intermediates and pathways differ.
  • Discuss the factors that influence the stability and reactivity of the $Br^+$ intermediate in nucleophilic aromatic substitution reactions, and explain how these factors impact the overall reaction.
    • The stability and reactivity of the $Br^+$ intermediate in S$_N$Ar reactions are influenced by several factors. The presence of electron-withdrawing groups on the aromatic ring can stabilize the $Br^+$ intermediate by delocalizing the positive charge, making the carbon more susceptible to nucleophilic attack. Additionally, the nature of the leaving group (e.g., halide) can affect the ease of $Br^+$ formation, with better leaving groups (e.g., iodide) facilitating the generation of the $Br^+$ intermediate. The stability of the $Br^+$ intermediate, in turn, impacts the rate and efficiency of the overall nucleophilic aromatic substitution reaction, as a more stable $Br^+$ species is more readily attacked by the nucleophile, leading to faster and more favorable substitution.

"$Br^+$" also found in:

© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.
Glossary
Guides